Given: i=10A,B=0.15 T,θ=45
∘
and l=2 m
Force on a current carrying wire of finite length =
F
=l(
i
×
B
)
Hence, magnitude of force, F=Bilsinθ
=0.15×10×2×sin45
=
2
3
N
Answer:16
Step-by-step explanation:
as F=BIL so by placing value's B is magnetic field 4 and i is current 2A and l is length that js 2 m so answer is
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