Answer:
19x20
Explanation:
The area of a rectangle is given by the formula A = l * w, where l is the length and w is the width of the rectangle. In this case, we are given that the area of the rectangle is 380 square meters and that the length and width of the rectangle are consecutive integers.
We can use this information to create a system of equations to solve for the length and width of the rectangle. Let l be the length of the rectangle and w be the width of the rectangle. Since the length and width of the rectangle are consecutive integers, we have:
l = w + 1
Substituting this equation into the formula for the area of the rectangle, we get:
A = l * w
= (w + 1) * w
= w² + w
Since the area of the rectangle is given as 380 square meters, we can set this equation equal to 380 and solve for w:
w² + w = 380
To solve for w, we can use the quadratic formula, which is given by:
x = (-b ± √(b² - 4ac)) / (2a)
where a, b, and c are the coefficients of the quadratic equation, and x is the solution. Substituting the values of a, b, and c into the formula and simplifying, we get:
w = (-1 ± √(1² - 4(1)(380))) / (2(1))
= (-1 ± √(-1519)) / 2
Since the length and width of the rectangle must be positive integers, we can ignore the negative solution and only consider the positive solution. Therefore, the width of the rectangle is 19.
To find the length of the rectangle, we can use the equation l = w + 1 that we derived earlier. Substituting the value of w into this equation, we get:
l = w + 1
= 19 + 1
= 20
Therefore, the length of the rectangle is 20 and the width of the rectangle is 19. The dimensions of the rectangle are 20 x 19.