Explanation:
the angle south-east of x is hard to read.
I assume this is 86 (but could be also 96).
remember, the sum of all angles in a triangle is always 180°.
and the intersection angles between 2 lines are the same in both sides of the lines. the only difference between above and below angles is that they are left-right mirrored.
so,
180 = x + 22 + 86
x = 180 - 22 - 86 = 72°
x and y are intersection angles of 2 lines and are therefore equal (due to the left-right mirroring).
y = x = 72°
180 = w + 33 + 72
w = 180 - 33 - 72 = 75°
remember also that the sum of all angles around a single point on one side of a line is always 180°, because the line can be seen as diameter of a circle with the point being the circle center. and the degrees of a half-circle are 180°.
180 = angle1 + unnamed angle = angle1 + 85
angle1 = 180 - 85 = 95°
180 = angle2 + angle3 + unnamed angle =
= 42 + angle3 + 85
angle3 = 180 - 42 - 85 = 53°
for the third question we don't see a picture of the situation. I assume this is a circle with O being the center of the circle, and Q, N, P are points on the circle arc.
it is not clear, if the angle QOP is part of the angle QON, or if they are separate segments of the circle.
if the angle QOP is part of the angle QON, then the angle PON = 142 - 46 = 96°
if the angle QOP is separate from the angle QON, then the angle PON = 360 - 142 - 46 = 172°