Question

144000x²+431974x-39=0 find the value of X​

Answer 1

`x=0.00009028, x=-2.999909725`

Explanation:

Use the quadratic formula:

`x=(-b \pm √(b^2-4ac) )/(2a)`

when
`ax^2+bx+c=0`

Therefore, for
`144000x^2+431974x-39=0`

a = 144,000 b = 431,974 and c = -39

Substituting this data into the quadratic formula:

`x=(-431974 \pm √(431974^2-4(144000)(-39)) )/(2(144000))`

`x=0.00009028, x=-2.999909725`