144000x²+431974x-39=0 find the value of X

Question

asked Jan 7, 2023 132k views

1 Answer

AdamG · Answer 1 · 2023-01-12T18:50:16+0000

Answer:

x=0.00009028, x=-2.999909725

Explanation:

Use the quadratic formula:

$x=(-b \pm √(b^2-4ac) )/(2a)$

when
ax^2+bx+c=0

Therefore, for
144000x^2+431974x-39=0

a = 144,000 b = 431,974 and c = -39

Substituting this data into the quadratic formula:

$x=(-431974 \pm √(431974^2-4(144000)(-39)) )/(2(144000))$

x=0.00009028, x=-2.999909725