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What are the vertex and range of y = |2x + 6| + 2? 1 (0, 2); 2 < y < ∞ 2 (0, 2); −∞ ≤ y < ∞ 3 (−3, 2); 2 < y < ∞ 4 (−3, 2); −∞ ≤ y < ∞

2 Answers

7 votes

Answer:

The answer is c, or (3, 2), 2 less than y is greater than infinity

Explanation:

I got it right on the test

Have a good day and hope it helps!

User Daerik
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2 votes

Answer: The vertex is at (-6, 2). The range is 2 < y < ∞.

Explanation:

y = |2x + 6| + 2 is almost in vertex form, which is y = |x - h| + k. We will divide both values by 2, so the 2 coefficient is on the outside, y = 2|x + 3| + 2.

After this, we can see that the vertex is at (-h, k). This means the vertex is at (-3, 2).

For the range, since this V (the shape of an absolute value graph) opens upwards, it will be everything greater than and equal to the y value of the vertex, in this case, 2. That means our range is;

2 < y < ∞

What are the vertex and range of y = |2x + 6| + 2? 1 (0, 2); 2 < y < ∞ 2 (0, 2); −∞ ≤ y-example-1
User Hevar
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