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Need Answered ASAP. Rewrite 12x^4y^3 − 48x^3y^4 using a common factor.

User Wuwucat
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Answer:

Explanation:

12x^2y^3-36x^5y^3-48x^4y4

factor out 12

12(x^2y^3-3x^5 y^3 - 4x^4 y^4

consider X^2 y^3 - 3x^5 y^3

4x^4 y^4 Factor out x^2y^3

x^2 y^3 (1-3x^3 -4x^2 y)

Rewrite the complete factored expression

12x^2 y^3 (1-3x^3-4x^2y)

User Fouad Boukredine
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