Answer:
4 Inches.
Explanation:
To find the width of Frank's scale model, we need to first determine the scale of the model. This can be done by dividing the height of the real Eiffel Tower by the height of Frank's model. Since the real Eiffel Tower is 984 feet tall and Frank's model is 12 inches tall, the scale of the model is 984 / 12 = 82 feet per inch.
Next, we can use this scale to determine the width of the model. Since the real Eiffel Tower is 328 feet wide at its base, and the scale of the model is 82 feet per inch, the width of the model must be 328 / 82 = 4 inches.
Therefore, the width of Frank's scale model of the Eiffel Tower must be 4 inches.