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What are the roots of the quadratic equation y=x^2-10x+125

What are the roots of the quadratic equation y=x^2-10x+125-example-1

2 Answers

1 vote

Answer:

B. x = 5 ± 10i

Explanation:

ax² + bx + c = 0

quadratic formula = (-b ±
\sqrt{b^(2)-4ac })/2a

y = x² - 10x + 125

substitute the values:

(-(-10) ±
\sqrt{(-10)^(2)-4(1)(125) })/2(1)

= (10 ±
√(100 - 500))/2

= (10 ±
√(-400))/2

= (10 ± 20i)/2

= 5 ± 10i

User Daryl Gill
by
7.7k points
2 votes

B would be the answer to this quadratic equation.

User MystikSpiral
by
8.2k points

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