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Given the function y= x2 + 10x +16=0
What are the x-intercepts of the function?

Given the function y= x2 + 10x +16=0 What are the x-intercepts of the function?-example-1
User Kerberos
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4.9k points

2 Answers

4 votes

Answer:

(-2,0) and (-8, 0)

Explanation:

Factor the function:

(x + 2)(x+8) = 0

x = -2, -8

x intercepts are when y=0

Coordinates are:

(-2,0) and (-8, 0)

User Mike Brant
by
5.0k points
4 votes

Answer:

(0,-8) and (0,-2)

Explanation:

Factorize: x² + 10x + 16 = 0

You'll get: (x + 8)(x + 2) = 0

The roots are x = -8 and x = -2

So the curves intercepts the x-axis at (0,-8) and (0,-2)

User Pjhades
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4.5k points