Question

If Emily throws the ball at an angle of 30˚ below the horizontal with a speed of 12m/s, how far from the base of the dorm should Allison stand to catch the ball?

Assume the vertical distance between where Emily releases the ball and Allison catches it is 4.0m

Answer 1

Refer to the photo taken.

Answer: 4.98m

Answer 2

5 m

Step-by-step explanation:

Allison is 4 m LOWER than Emily

vertical component = 12 * sin(-30) = - 6 m/s

vertical distance equation

d = do + vot + 1/2 at^2

- 4 = 0 + -6 t + 1/2 (-9.81) t^2

- 4.905 t^2 - 6t + 4 = 0 Use Quadratic Formula to find t =.479 s

So the ball flies with its HORIZONTAL component for .479 s then Alli catches it

Horizontal component = 12 cos(- 30) = 10.4 m/s

10.4 m/s * .479 s = 4.977 =~ 5 m