Answer:
To solve this problem, we need to determine how many boxes of each type the company should make to maximize their profit. We can set up a system of equations to represent the number of apples in each box and the total number of apples the company has.
Let's call the number of boxes of type A x, the number of boxes of type B y, and the number of boxes of type C z. We can represent the number of apples in each box using the following equations:
x + y + z = 2800
4x + 6y + 0z = 2200
2x + 2y + 6z = 2300
To maximize the profit, the company should make as many boxes as possible while still having enough apples to fill all the boxes. We can solve this system of equations using substitution to find the values of x, y, and z that maximize the profit.
First, we can solve the first equation for z in terms of x and y:
z = 2800 - x - y
Next, we can substitute this expression for z into the second and third equations to eliminate z:
4x + 6y + 0(2800 - x - y) = 2200
4x + 6y = 2200
2x + 2y + 6(2800 - x - y) = 2300
2x + 2y + 17600 - 6x - 6y = 2300
2x + 2y = -15300
We can then solve this system of equations using substitution. From the second equation, we have:
4x + 6y = 2200
2x + 2y = -15300
We can solve the second equation for y in terms of x:
y = -15300/2 - x/2
We can substitute this expression for y into the first equation to solve for x:
4x + 6(-15300/2 - x/2) = 2200
4x - 45300 - 3x = 2200
x = (2200 + 45300) / (4 - 3)
x = 13600/1
x = 13600
We can then use this value of x to find the value of y:
y = -15300/2 - 13600/2
y = -13650
Finally, we can use these values of x and y to find the value of z:
z = 2800 - 13600 - (-13650)
z = 1650
Therefore, the company should make 13600 boxes of type A, -13650 boxes of type B, and 1650 boxes of type C to maximize their profit.
Explanation: