Answer:
(-infinity, -2) ∪ (-3, infinity).
Explanation:
To solve this compound inequality, we need to first solve each inequality separately. For the first inequality, 4(z+1) > -4, we can distribute the 4 to get 4z + 4 > -4. Then, we can subtract 4 from both sides to get 4z > -8. Finally, we can divide both sides by 4 to get z > -2.
For the second inequality, 2z - 4 < -10, we can add 4 to both sides to get 2z < -6. Then, we can divide both sides by 2 to get z < -3.
Now that we have solved both inequalities, we need to consider their intersection. Since the inequalities are joined by the "or" operator, the solution is the union of the solutions to each inequality. In interval notation, this is represented as the union of the intervals (-infinity, -2) and (-3, infinity).
Therefore, the solution to the compound inequality in interval notation is (-infinity, -2) ∪ (-3, infinity).