Question

The length of a rectangle is 3yds less than double the width, and the area of the rectangle is 44yd^2 . Find the dimensions of the rectangle.

Answer 1

length = 8 yds

width = 5.5 yds

Explanation:

Area of rectangle = l * w

w = width

length = 2w - 3

Substitute l with 2w - 3:

(2w - 3)*w = 44

2w² - 3w = 44

2w² - 3w - 44 = 0

Solve for w (AC method):

2w² + 8w - 11w - 44 = 0

2w(w + 4) - 11(w + 4) = 0

(2w - 11)(w + 4) = 0

w = 5.5 or w = -4

note: length cannot be negative, so w = 5.5 yds

Substitute w with 5.5 in either equation:

5.5 * l = 44 yds²

l = 44/5.5 = 8 yds

or

l = 2(5.5) - 3

l = 11 - 3 = 8 yds