Question

A cannon is fired horizontally at 235 m/s off of a 61 meter tall, shear vertical cliff. How many seconds will have elapsed before the cannon ball strikes the ground? Round to the nearest hundredth.

Answer 1

Hope this helps!

Step-by-step explanation:

The time elapsed before the cannon ball strikes the ground can be found by using the equation for kinematic vertical motion,

t = (2*d)/g

Where d is the vertical distance and g is the acceleration due to gravity (9.8 m/s^2).

t = (2*61)/9.8

t = 12.24 seconds

The time elapsed is 12.24 seconds, rounded to the nearest hundredth is 12.24 seconds.