Question

A gas has an initial volume o 5.32L at 371K. The same gas now has a volume of 4.90 Lat 273

K and 1.03 atm. What was the original pressure of the gas?
Type your answer...

Answer 1

Answer:1.29atm

Explanation: We are given P2,V1,V2,T1, and T2. We are looking for P1.

We can plug it into the combined gas laws formula.

`((P1)(V1))/(T1) =((P2)(V2))/(T2)`

`P1=((P2)(T1)(V2))/((T2)(V1))`

P1 = ?

V1 = 5.31 L

T1 = 371 K

P2 = 1.03 atm

V2 = 4.90 L

T2 = 273 K

`P1 = ((1.03)(371)(4.90))/((273)(5.31)) \\`

P1 = 1.29 atm