Question

For the function N(t)=4|t+5|+3, evaluate N(2).

Answer 1

To evaluate N(2) for the function N(t) = 4|t+5| + 3, we substitute 2 into the function, compute the absolute value, and perform the arithmetic operations to find that N(2) equals 31.

Step-by-step explanation:

To evaluate the function N(t) = 4|t+5| + 3 for N(2), first substitute the value of t with 2:

N(2) = 4|2+5| + 3

Next we determine the absolute value:

N(2) = 4|7| + 3 = 4 × 7 + 3

Now, perform the multiplication:

N(2) = 28 + 3

Finally, add the numbers to find the value of the function:

N(2) = 31

Therefore, the function evaluated at t = 2 is N(2) = 31.

Answer 2

see explanation

Step-by-step explanation:

N(t)=4|t+5|+3, evaluate N(2).

Evaluate: Plug in a number for each variable.

4(|t+5|)+3

t=2

Evaluate for t=2

4(|2+5|)+3

4(|2+5|)+3

=31

(Hope this answer does you some good )