Answer:
Length of DF = 3y + 9
Explanation:
Given:
ΔABC is similar to ΔDEF
Line EF = 6y
Find:
Length of DF
Computation:
Given that ΔABC is similar to ΔDEF
So,
Line BC similar to Line EF
Line BA similar to Line ED
Line AC similar to Line DF
Common factor = EF/BC
Common factor = 6y/2y
Common factor = 3
So,
Line AC similar to Line DF
So,
DF = 3[AC]
Length of DF = 3[y+3]
Length of DF = 3y + 9