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PLEASE HELP THE QUESTION IN THE PICTURE.

PLEASE HELP THE QUESTION IN THE PICTURE.-example-1
User Ben Wilber
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1 Answer

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Answer:

The first expression, (5^2*x^6*y^(-7))(5*x^0*y^28)

Explanation:

Basically, add up the exponents for each unique base. We have two exponents with bases of 5 in this expression, 5^2 and 5 (which is equal to 5^1). Add the exponents together to get 3, so you have 5^3 = 125.

Add up the exponents for bases of x this time. We have x^6 and x^0. 6 + 0 = 6, so we have x^6.

Finally add up the exponents for bases of y. We have y^28 + y^(-7) = 28 + (-7) = 21, so we have y^21.

User Maticzav
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