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42 votes
42 votes
Could someone help me, please?

Could someone help me, please?-example-1
User Erik Bennett
by
2.4k points

2 Answers

15 votes
15 votes

B = 180 - 90 - 33 = 57°

C in DCB tringle = 180 - 90 - 57 = 33°

So C in DCB triangle = 33°

User Jeadonara
by
2.1k points
24 votes
24 votes

Answer:

33°

Explanation:

<ACD =90-33 =57°

<DCB=<ACB - <ACD

=90° -57 =33°

In triangle ACD the only angle that has not been found is <ACD so you find it by adding 90+33 and subtracting from 180° to get 57°. <ACB =90° and <ACD = 57° ,the angle in question is<DCB which is part of< ACB. So to get <DCB you do 90°-57°=33°.

User Pheonyx
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2.9k points