Answer:
Future amount = 100(1.9)^5 ;
2476
Explanation:
P(t) = P0 * (1 + r)^t
P(t) = 100 * (1 + 90/100)^t#
P(t) = 100 * (1 + 0.9)^t
Therefore, the number of bacteria in 5 years :
P(5) = 100 * (1 + 0.9)^5
P(5) = 100 * (1.9)^5
P(5) = 100 * 24.76099
P(5) = 2476.099
P(5) = 2476 bacteria
P(10%