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Situation: Find the substance's half-life, in days. Round your answer to the nearest tenth. A 50 gram sample of a substance that's used to treat thyroid disorders has a k- value of 0.1133. Enter the correct answer. N = Noe -kt DONE No = initial mass (at time t = 0) 1? N = mass at time t k = a positive constant that depends on the substance itself and on the units used to measure time t = time, in days

Find the substance's half-life , in days.
Round your answer to the nearest tenth.​

User Arreane Diez Coyoca
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1 Answer

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19 votes

Answer:

The substance's half-life is 6.1 days.

Explanation:

The half-life of the substance can be calculated by knowing the constant decay:


t_(1/2) = (ln(2))/(k)

k: is the decay constant = 0.1133 d⁻¹

Hence, the half-life is:


t_(1/2) = (ln(2))/(k) = (ln(2))/(0.1133 d^(-1)) = 6.1 d

Therefore, the substance's half-life is 6.1 days.

I hope it helps you!

User Hariharan L
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