Question

write the equation in point slope form of the line that is perpendicular to 3x-2y=-8 going through the point (-6,5

Answer 1

y-5 = -2/3 (x+6)

Explanation:

-2y = -3x -8

2y = 3x + 8

2/2 y = 3/2 x + 8/2

y = 3/2 x + 4

slope of a perpendicular line

- 2/3

y-5= -2/3(x-(-6)

y-5 = -2/3 (x+6)