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29 votes
29 votes
6.

3. A 7.6 kg object is pulled 6.0 m at a constant
velocity of 5.0 m/s along a horizontal surface by
a force of 2.0 N. What is the work done on the
object to overcome friction?

User Azizi Musa
by
2.4k points

1 Answer

22 votes
22 votes

Answer:

12 J

Step-by-step explanation:

From the question given above, the following data were obtained:

Mass (m) = 7.6 kg

Distance (d) = 6 m

Velocity (v) = 5 m/s

Force (F) = 2 N

Workdone (Wd) =.?

Workdone can be defined as the product of force and distance moved in the direction of the force. Mathematically, it is expressed as:

Workdone = Force × distance

Wd = F × d

With the above formula, we can obtain the workdone as follow:

Distance (d) = 6 m

Force (F) = 2 N

Workdone (Wd) =.?

Wd = F × d

Wd = 2 × 6

Wd = 12 J

Thus, the workdone is 12 J

User Chyna
by
3.0k points