Question

Two sides of a parallelogram are 49 feet and 78 feet. The measure of the angle

between these sides is 59º. Find the area of the parallelogram to the nearest square
foot.

Answer 1

`A=3276\ ft^2`

Explanation:

Given that,

The sides of a parallelogram are 49 feet and 78 feet. The measure of the angle between these sides is 59º.

We need to find the area of the parallelogram.

Using trigonometry,

`\sin(59)=(h)/(49)\\\\h=\sin(59)* 49\\\\h=42.00\ ft`

We know that,

Area = base (b) × height (h)

So,

`A=78* 42.00\\\\A=3276\ ft^2`

So, the area of the parallelogram is equal to
`3276\ ft^2`.