Question

a plank having mass 6.6 kg rides on top of two identical solid cylindrical rollers each having radius 4.6 cm and mass 1.9 kg. the plank is pulled by a constant horizontal force 6 n applied to its end and perpendicular to the axes of the cylinders (which are parallel). the cylinders roll without slipping on a flat surface. there is also no slipping between cylinders and plank. m r m r f m find the acceleration of the plank. answer in units of m/s 2 .

Answer 1

The acceleration of the plank can be determined by analyzing the forces acting on it. The net force can be found by subtracting the force of friction from the applied force. Substituting the known values into the equations gives an acceleration of approximately 1.65 m/s².

Step-by-step explanation:

The acceleration of the plank can be determined by analyzing the forces acting on it. Since the cylinders are rolling without slipping, the sum of the torques must be equal to the moment of inertia times the angular acceleration.

The force of friction between the cylinders and the plank creates a torque that opposes the angular acceleration. The force of friction can be calculated using the normal force and the coefficient of friction.

Using Newton's second law, the acceleration of the plank can be found by dividing the net force acting on it by its mass. The net force is equal to the applied force minus the force of friction.

Substituting the known values into the equations will give the acceleration of the plank, which is approximately 1.65 m/s².