Answer:
1.) Option C
2.) Option B
3.) Option D
4.) Option A
Explanation:
![\frac{3x {}^(2) }{y {}^( - 3) } \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/u0njp7kzggv0sywu117sjy228xn5jyaifk.png)
Here, we know that
![a {}^( - 1) = (1)/(a) \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/7wgen2ad723wubtsx0wiwmp282naqb1da0.png)
So,
![\frac{ {3x}^(2) }{y {}^( - 3) } = \frac{ {3x}^(2) }{ \frac{1}{y {}^( 3) } } = {3x}^(2) y { }^(3) \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/klec3uz7my8zskaa7gsi9t9e4mq2hc3mx3.png)
Thus, Option C is correct
2.)
![( {4}^(0) )( {4}^(2) ) \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/7bwjkklcakmz5fdv9melhdwueqqhkp208x.png)
We know that,
n⁰ = 1
where, n = any real number
So,
![( {4}^(0) )(4 {}^(2) ) = 1 * 16 = 16 \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/c2pbj2jwzz8482eddp9ikf4et9t1fs8mps.png)
Thus, The answer is 16
3.)
![( (5)/(3) ) {}^( - 3) \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/lt9koppyafcd0ty04lsia5sfuvccqfq8wq.png)
We know that
![a {}^( - 1) = (1)/(a) \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/7wgen2ad723wubtsx0wiwmp282naqb1da0.png)
So,
![( { (5)/(3) )}^( - 3) = ( { (3)/(5) )}^(3) = (27)/(125) \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/93scbi1v94qvaylugt9dt4w0zsvrntdh40.png)
Thus, Option D is correct
4.)
![\frac{a {}^(2) {b}^(5)c {}^(0) }{ab {}^(7) } \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/5fjdwkohdo95clh10phv0q0wh3nl6tk9tw.png)
![\frac{a {}^(2) {b}^(5) c {}^(0) }{ab {}^(7) } = \frac{a}{ {b}^(2) } \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/a6sgimeilzxr9jbodxil77qc83ufdw246s.png)
Thus, Option A is correct
-TheUnknownScientist 72