Question

50 POINTS HELP ASAP

Which algebraic rule describes the reflection of quadrilateral ABCD to quadrilateral A'B'C'D'?
An image displaying two quadrilateral ABCD and A'B'C'D' in a graph with vertices. ABCD with vertices A of -5 comma -1, B of -3 comma -3, C of -5 comma -5 and D of -7 comma -3 and A'B'C'D' with vertices A' of 5 comma -1, B' of 3 comma -3, C' of 5 comma -5 and D' of 7 comma -3.

A.
(x, y) → (1 – x, 1 – y)

B.
(x, y) → (–x, y)

C.
(x, y) → (x, –y)

D.
(x, y) → (x – 1, y – 1)

Answer 1

B) (x, y) → (–x, y)

Hope This Helps <33

--Jax

Answer 2

• B) (x, y) → (–x, y)

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From the picture we see this is a reflection across the y-axis.

From the coordinates we see all x-coordinates have changed to opposite and all y-coordinates remained as is.

The rule for such reflection is:

• (x, y) → (–x, y)

This is the option B.