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Two planes, which are 2920 miles apart, fly toward each other. Their speeds differ by 80mph. If they pass each other in 4 hours, what is the speed of each?

User GarethPrice
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1 Answer

25 votes
25 votes

9514 1404 393

Answer:

405 mph; 325 mph

Explanation:

The total of their speeds is ...

2920 mi/(4 h) = 730 mi/h

If s represents the speed of the slower plane, then we have ...

s + (s+80) = 730

2s = 650 . . . . . . . subtract 80

s = 325 . . . . . . . divide by 2

s+80 = 405 . . . find the faster speed

The speeds of the planes are 405 mi/h and 325 mi/h.

User Eric Schoonover
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