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7 votes
7 votes
HELP!!

An electric motor is used to lift an elevator and
occupants (mass = 1.50 x 10kg) to a helght of
15.0 m in 30.0 s at a constant velocity. What is
the power output of the motor? I know the answer I just need someone to show me the steps so I understand how to solve this


Answer: (7.35 x 10^3 W)

User Alex Mathew
by
2.5k points

1 Answer

8 votes
8 votes

Answer:


P=7.35* 10^(3)\ W

Step-by-step explanation:

Given that,

Mass,
m=1.5* 10^2\ kg

It lifts to a height of 15 m in 3 s

We need to find the power of the motor. The formula for power is given by :


P=(W)/(t)\\\\P=(mgh)/(t)\\\\P=(1.5* 10^2* 9.8* 15)/(3)\\\\P=7.35* 10^(3)\ W

So, the power of the motor is equal to
7.35* 10^(3)\ W.

User Michael Lawrence
by
2.8k points