Question

How many grams is 2.393 x 10^24 atoms of CI

70.45 g CI
140.9 ga
140.9 mole CI
70.45 mole CI

Answer 1

There are 140.9 grams in 2.393*10²⁴ aotms of Cl.

Step-by-step explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023*10²³ atoms are contained in 1 mole of the compound, 2.393*10²⁴ atoms are contained in how many moles?

`amount of moles=(2.393*10^(24) *1 mole)/(6.023*10^(23) )`

amount of moles= 3.973

If the molar mass of Cl is 35.453
`(g)/(mole)`, then the amount of mass that contains 3.973 moles can be calculated as:

3.973 moles*35.453
`(g)/(mole)`= 140.85 grams ≅ 140.9 grams

There are 140.9 grams in 2.393*10²⁴ aotms of Cl.