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35 votes
35 votes
How many grams is 2.393 x 10^24 atoms of CI

70.45 g CI
140.9 ga
140.9 mole CI
70.45 mole CI

User Romesh
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1 Answer

7 votes
7 votes

Answer:

There are 140.9 grams in 2.393*10²⁴ aotms of Cl.

Step-by-step explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023*10²³ atoms are contained in 1 mole of the compound, 2.393*10²⁴ atoms are contained in how many moles?


amount of moles=(2.393*10^(24) *1 mole)/(6.023*10^(23) )

amount of moles= 3.973

If the molar mass of Cl is 35.453
(g)/(mole), then the amount of mass that contains 3.973 moles can be calculated as:

3.973 moles*35.453
(g)/(mole)= 140.85 grams ≅ 140.9 grams

There are 140.9 grams in 2.393*10²⁴ aotms of Cl.

User Ggirodda
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