Answer:
the answer is:
1.33x10^23 molec. of Ca(OH)_2
Step-by-step explanation:
12.6 g of ca(oh)2 | 1 mol of Ca(OH)2 | 6.022x10^23 molec of Ca(OH)2
| 57.09 g of ca(oh)2) | 1 mol of ca(oh)2
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