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A baker sells 3 cakes and 1 pie for 44.50$ to Natasha.

He sells 2 cakes and 1 pie to Brian for 32.50$
Solve the system to determine the price of 1 cake and the price of 1 pie.

3c + p= 44.50
2c + p = 32.60

A baker sells 3 cakes and 1 pie for 44.50$ to Natasha. He sells 2 cakes and 1 pie-example-1

1 Answer

2 votes

Answer:

C = $12

P = $8.50

Explanation:

First take $44.50 and subtract $32.50 from it and you should get $12 which if you analyze the problem you would notice that Natasha has 3 cakes and Brian has 2 cakes. Both Natasha and Brian have 1 pie, so $12 has to equal the amount each cake cost. Now that You know the cost, multiply 12 by 2 or by 3. If you multiplied it by 2 you should get 24 ad if you multiplied it by 3 you should get 36. after you get those two numbers You will take your two totals and subtract. For Natasha you will subtract 44.50 - 36 and for Brian you will subtract 32.50 - 24. For both equations you will get 8.50 which is the cost for the pies each. So that means C = $12 P = $8.50

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