Question

What are the solutions of x^2-2x+37=0

Answer 1

`x=1\pm6i`

Explanation:

`x^2-2x+37=0\\x^2-2x+1+36-36=0-36\\(x-1)^2=-36\\(x-1)^2=i^2\cdot6^2\\x-1=\pm6i\\x-1+1=\pm6i+1\\x=1\pm6i`

Answer 2

Answer: x=1±6i

Explanation:

`\displaystyle\\x^2-2x+37=0\\\\D=(-2)^2-4(1)(37)\\\\D=4-148\\\\D=-144\\\\√(D)=√(-144) \\\\√(D)=√(12^2(-1)) \\\\√(D)=12√(-1) \\\\√(D)=12i\\\\x=(-(-2)б12i)/(2) \\\\x=(2б12i)/(2)\\\\x=(2(1б6i))/(2) \\\\x=1б6i`