Answer: The required system of linear equations is y = -4x + 1 and y = 5x - 8.
Explanation:
Here,
The slope-intercept form of linear equation.
y = mx + c - - - - - (1)
Equation of line 1
Since point (-1, 5), (0, 1) lies on the line 1.
The slope of line 1,
m = 1-5 / 0+1
m = -4
Now put this slope and 1 point in the equation.
5 = -4(-1) + c
c = 5 - 4
c = 1
now, put m and c in equation 1
y = - 4x + 1
Similarly, the equation of line 2 is given as y = 5x - 8.
Thus, the required system of linear equations is y = -4x + 1 and y = 5x - 8.
I hope this helps :3