Answer:
B) Width 1/3, Length 6 + x, Area as a product of width times length 1/3 (6+x), Area as a sum of the areas of smaller rectangles ((1/3) * 6) + 1/3x
C) Width r, Length 1+1+1, Area as a product of width times length r(1+1+1), Area as a sum of the areas of smaller rectangles r1+r1+r1
D) Width 6, Length p+p+p+p, Area as a product of width times length 6(p+p+p+p), Area as a sum of the areas of smaller rectangles 6p+6p+6p+6p
E) Width m, Length 6 + 8, Area as a product of width times length m(6 + 8), Area as a sum of the areas of smaller rectangles m6 + m8
F) Width 5, Length 3x + 8, Area as a product of width times length 5(3x + 8), Area as a sum of the areas of smaller rectangles 5(3x) + (5*8)
Explanation:
Area would be the width times length and for the areas as the sum you would just calculate the area of the smaller rectangles and add them.