Question

Io completes one (circular) orbit of Jupiter in 1.77 days. The distance from Jupiter to Io is 4.22×108m. Centripetal acceleration

Answer 1

Using the formulas
`(v^2)/(r)=\alpha \\` and
`v= (2\pi r)/(T)` ,combine them to get:

`((((2\pi r))/(T))^2)/(r) = \alpha`

solve for α, where α is centripetal acceleration, T is period in seconds, and r is radius.

`(17418.895^2)/(4.22*10^8) = \alpha \\0.72 = \alpha`