Question

What is the electric field at a point

0.450 m to the left of a
5.77*10^-9 C charge?
Include a + or - sign to indicate the
direction of the field.

(Unit = N/C)

Answer 1

E = 256.444 N/C

Step-by-step explanation:

E = kq/r²

E = 9*10^9 * 5.77*10^-9/(0.450)²

E = 51.93/0.2025

E = 256.444 N/C