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Find the rational roots of polynomial 2x^3+3x^2-11x-6

1 Answer

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Answer: x=-3 x=2 x=-0,5

Explanation:

2x³+3x²-11x-6=

2x³+(6x²-3x²)-11x-6=

(2x³+6x²)-3x²-11x-6=

2x²(x+3)-(3x²+11x+6)=

2x²(x+3)-(3x²+(9x+2x)+6)=

2x²(x+3)-((3x²+9x)+(2x+6))=

2x²(x+3)-(3x(x+3)+2(x+3))=

2x²(x+3)-(x+3)(3x+2)=

(x+3)(2x²-(3x+2))=

(x+3)(2x²-3x-2)=

(x+3)(2x²-4x+x-2)=

(x+3)(2x(x-2)+(x-2))=

(x+3)(x-2)(2x+1)

(x+3)(x-2)(2x+1)=0

x+3=0

x=-3

x-2=0

x=2

2x+1=0

2x=-1

Divide both parts of the equation by 2:

x=-0.5

User Zerocewl
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