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Calculate the potential of a zinc/silver voltaic cell in which the zinc electrode is immersed in 0.500 M zinc nitrate and the silver electrode is in 0.100 M silver nitrate. Ag (aq) + e -> Ag(s) +0.80 Zn(aq)
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Calculate the potential of a zinc/silver voltaic cell in which the zinc electrode is immersed in 0.500 M zinc nitrate

and the silver electrode is in 0.100 M silver nitrate.
Ag (aq) + e -> Ag(s) +0.80
Zn(aq) + 2e -> Zn(s) -0.76

User Doan
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2 votes

Answer:

Potential = 0.80 - 0.76 = 0.04 V

User Manuel Spezzani
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