Question

Find the derivative. y = sinh−1(tan(x))

Answer 1

-sinh(1)sec^2(x)

Explanation:

The notation that I suppose you're using is d/dx.

Starting with

y = sinh−1(tan(x))

Simplify the trigonometric ratio sinh, then simplify:

d/dx(sinh(-tan(x))

d/dx [-sinh(1)tan(x)]

=-sinh(1) * d/dx [tan(x)]

Therefore, you get:

-sinh(1)sec^2(x)