Question

A bullet with a mass of 0.020 kg collides with a 2.5 kg wooden block at

rest. After the collision, the bullet and the block travel at a speed of 1.2
m/s. What is the velocity of the bullet BEFORE the collision? *

Answer 1

151.2 m/s

Step-by-step explanation:

m1 = 0.020 kg

m2 = 2.5 kg

vf = 1.2 m/s

m1v1 +m2v2 = (m1 +m2)vf

0.020v1 + 0 = (0.020 +2.5)(1.2)

---> 151.2 m/s