Question

A rental car company charges $40.18 per day to rent a car and $0.05 for every mile driven. Jacob wants to rent a car, knowing that:

He plans to drive 75 miles.
He has at most $270 to spend.

Which inequality can be used to determine dd, the maximum number of days Jacob can afford to rent for while staying within his budget?

A. 270≥40.18(3.75+d)
b.270≥40.18d+3.75
c.270≤40.18d+3.75
d.270≤40.18(3.75+d)

Answer 1

Answer: 270 ≥ 40.18d + 3.75

Answer 2

b) 270 ≥ 40.18d + 3.75

Explanation:

Per day is a variable, so it's 40.18d

Per mile is also a variable so 0.05m

40.18d + 0.05m ≤ 270

40.18d + 0.05(75) ≤ 270

40.18d + 3.75 ≤ 270