Question

Karen invested her savings in two investment funds. The $6000 that she invested in Fund A returned a 1% profit. The amount that she invested in Fund B returned a 4% profit. How much did she invest in Fund B, if both funds together returned a 3% profit?

Answer 1

Karen invested $1800 - $6000 = $<<1800-6000=4200>>4200 in Fund B.

Explanation:

To calculate the amount that Karen invested in Fund B, we can set up the following equation:

(0.01 * 6000) + (0.04 * x) = 0.03 * (6000 + x)

Where x is the amount of money that Karen invested in Fund B. We can solve for x by rearranging the terms in the equation as follows:

0.01 * 6000 + 0.04 * x = 0.03 * 6000 + 0.03 * x

Subtracting 0.03 * x from both sides gives us:

0.01 * 6000 + 0.04 * x - 0.03 * x = 0.03 * 6000 + 0.03 * x - 0.03 * x

Combining like terms on the left side gives us:

0.01 * 6000 + 0.01 * x = 0.03 * 6000

Dividing both sides by 0.01 gives us:

6000 + x = 1800

Subtracting 6000 from both sides gives us:

x = 1800 - 6000

Therefore, Karen invested $1800 - $6000 = $<<1800-6000=4200>>4200 in Fund B.