Question

Each onion ring had 45 calories and each slider have 325 calories, a combination meal with onions rings is a total of 920 calories and 3 times as many onion rings as there are sliders, white a system of equation

Answer 1

To solve the given system of equations, let's define variables x and y as the number of sliders and onion rings, respectively. We can set up the system based on the given information and then solve for the values of x and y. The solution is x = 2 and y = 6, meaning there are 2 sliders and 6 onion rings in the combination meal.

Step-by-step explanation:

Let's define the variables:

x = number of sliders

y = number of onion rings

According to the given information, each onion ring has 45 calories and each slider has 325 calories. The combination meal with onion rings has a total of 920 calories. Also, there are three times as many onion rings as there are sliders.

Based on these definitions, we can set up the following system of equations:

1. 45y + 325x = 920 (equation 1) - represents the total calorie count of the meal
2. y = 3x (equation 2) - represents the relationship between the number of onion rings and sliders

To solve this system of equations, we can substitute equation 2 into equation 1:

45(3x) + 325x = 920

135x + 325x = 920

460x = 920

x = 2

Substituting the value of x back into equation 2, we can find the value of y:

y = 3(2) = 6

So, there are 2 sliders and 6 onion rings in the combination meal.

Answer 2

Number of onion rings in the combination = x = 6

Number of sliders in the combination = y = 2

Step-by-step explanation:

At a particular restaurant, each onion ring has 45 calories and each slider has 325 calories. A combination meal with onion rings and sliders is shown to have 920 total calories and 3 times as many onion rings as there are sliders. Write a system of equations that could be used to determine the number of onion rings in the combination meal and the number of sliders in the combination meal. Define the variables that you use to write the system.

Let

Number of onion rings in the combination = x

Number of sliders in the combination = y

45x + 325y = 920 (1)

3 times as many onion rings as there are sliders

x = 3y (2)

Substitute x = 3y into (1)

45x + 325y = 920

45(3y) + 325y = 920

135y + 325y = 920

460y = 920

y = 920/460

y = 2

Substitute y = 2 into (2)

x = 3y

x = 3(2)

x = 6

Number of onion rings in the combination = x = 6

Number of sliders in the combination = y = 2