Question

Evaluate(8−3i)(3+2i)​

Answer 1

The answer is 30+7i.

Explanation:

Imaginary Number Definition

`\large\boxed{{i=√(-1)}}`

Simply evaluate like how you evaluate polynomials. Expand the expression in.

`\large{(8-3i)(3+2i)=[(8*3)+(8*2i)]+[(-3i*3)+(-3i*2i)]}\\\large{(8-3i)(3+2i)=(24+16i)+(-9i-6i^2)`

Therefore, our new expression when cancelling out the brackets is:

`\large\boxed{24+16i-9i-6i^2}`

Imaginary Number Definition II

`\large\boxed{i^2=-1}`

Therefore, substitute or change i² to -1

`\large{24+16i-9i-6(-1)}\\\large{24+7i+6}\\\large{30+7i}`

Complex Number Definition

`\large\boxed{a+bi}`

Where a = Real Part and bi = Imaginary Part.

Therefore, it's the best to arrange in the form of a+bi.

Hence, the answer is 30+7i.