Answer:
Explanation:
By writing it as 3(n-2) - n = 14 you can solve this to get n=10
You essentially let the bigger even consecutive number equal n, and therefore the smaller even number equals n-2. Three times the smaller even equals 3(n-2) and minus the bigger even number gives 3(n-2) - n which we know equals 14.
So 3(n-2) - n = 14
3n - 6 - n = 14
2n - 6 = 14
2n = 20
n = 10