Question

Which equation is perpendicular to the line represented by y = 6x +10 and passes through the ordered pair (5, -8)?

1.y+8= -1/6(x - 5)
2.y-5= (1/6x+8)
3.y-(-8)= -6(x - 5)
4.y+8 6(x - 5)

Answer 1

option 1

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 6x + 10 ← is in slope- intercept form

with slope m = 6

given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(6)`

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

here m = -
`(1)/(6)` and (a, b ) = (5, - 8 ) , then

y - (- 8) = -
`(1)/(6)` (x - 5 ) , that is

y + 8 = -
`(1)/(6)` (x - 5) ← equation of perpendicular line