Answer: x=1
Explanation:
Assume that "log" is the base-10 logarithm
log (2x)+log (5)=1
log 10{10}(2x)+log (5)=1
Assume that "log" is the base-10 logarithm
\log 10{10}(2x)+\log (5)=1
\log 10{10}(2x)+\log10{10}(5)=1
Apply the logarithm product identity
\log 10{10}(2x)+\log 10{10}(5)=1
log 10{10}(2x x 5)}=1