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1 vote
Solve log 2x + log 5 = 1. Round to the nearest thousandth if necessary.

User Nowayz
by
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1 Answer

3 votes

Answer: x=1

Explanation:

Assume that "log" is the base-10 logarithm

log (2x)+log (5)=1

log 10{10}(2x)+log (5)=1

Assume that "log" is the base-10 logarithm

\log 10{10}(2x)+\log (5)=1

\log 10{10}(2x)+\log10{10}(5)=1

Apply the logarithm product identity

\log 10{10}(2x)+\log 10{10}(5)=1

log 10{10}(2x x 5)}=1

User Andrew Lundgren
by
6.4k points
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